Theory Misc
theory Misc
imports Complex_Main
begin
chapter ‹Basic lemmas which do not belong to the particular domain of Timed Automata›
section ‹Reals›
subsection ‹Properties of fractions›
lemma frac_add_le_preservation:
fixes a d :: real and b :: nat
assumes "a < b" "d < 1 - frac a"
shows "a + d < b"
proof -
from assms have "a + d < a + 1 - frac a" by auto
also have "… = (a - frac a) + 1" by auto
also have "… = floor a + 1" unfolding frac_def by auto
also have "… ≤ b" using ‹a < b›
by (metis floor_less_iff int_less_real_le of_int_1 of_int_add of_int_of_nat_eq)
finally show "a + d < b" .
qed
lemma lt_lt_1_ccontr:
"(a :: int) < b ⟹ b < a + 1 ⟹ False" by auto
lemma int_intv_frac_gt0:
"(a :: int) < b ⟹ b < a + 1 ⟹ frac b > 0" by auto
lemma floor_frac_add_preservation:
fixes a d :: real
assumes "0 < d" "d < 1 - frac a"
shows "floor a = floor (a + d)"
proof -
have "frac a ≥ 0" by auto
with assms(2) have "d < 1" by linarith
from assms have "a + d < a + 1 - frac a" by auto
also have "… = (a - frac a) + 1" by auto
also have "… = (floor a) + 1" unfolding frac_def by auto
finally have *: "a + d < floor a + 1" .
have "floor (a + d) ≥ floor a" using ‹d > 0› by linarith
moreover from * have "floor (a + d) < floor a + 1" by linarith
ultimately show "floor a = floor (a + d)" by auto
qed
lemma frac_distr:
fixes a d :: real
assumes "0 < d" "d < 1 - frac a"
shows "frac (a + d) > 0" "frac a + d = frac (a + d)"
proof -
have "frac a ≥ 0" by auto
with assms(2) have "d < 1" by linarith
from assms have "a + d < a + 1 - frac a" by auto
also have "… = (a - frac a) + 1" by auto
also have "… = (floor a) + 1" unfolding frac_def by auto
finally have *: "a + d < floor a + 1" .
have **: "floor a < a + d" using assms(1) by linarith
have "frac (a + d) ≠ 0"
proof (rule ccontr, auto, goal_cases)
case 1
then obtain b :: int where "b = a + d" by (metis Ints_cases)
with * ** have "b < floor a + 1" "floor a < b" by auto
with lt_lt_1_ccontr show ?case by blast
qed
then show "frac (a + d) > 0" by auto
from floor_frac_add_preservation assms have "floor a = floor (a + d)" by auto
then show "frac a + d = frac (a + d)" unfolding frac_def by force
qed
lemma frac_add_leD:
fixes a d :: real
assumes "0 < d" "d < 1 - frac a" "d < 1 - frac b" "frac (a + d) ≤ frac (b + d)"
shows "frac a ≤ frac b"
proof -
from floor_frac_add_preservation assms have
"floor a = floor (a + d)" "floor b = floor (b + d)"
by auto
with assms(4) show "frac a ≤ frac b" unfolding frac_def by auto
qed
lemma floor_frac_add_preservation':
fixes a d :: real
assumes "0 ≤ d" "d < 1 - frac a"
shows "floor a = floor (a + d)"
using assms floor_frac_add_preservation by (cases "d = 0") auto
lemma frac_add_leIFF:
fixes a d :: real
assumes "0 ≤ d" "d < 1 - frac a" "d < 1 - frac b"
shows "frac a ≤ frac b ⟷ frac (a + d) ≤ frac (b + d)"
proof -
from floor_frac_add_preservation' assms have
"floor a = floor (a + d)" "floor b = floor (b + d)"
by auto
then show ?thesis unfolding frac_def by auto
qed
lemma nat_intv_frac_gt0:
fixes c :: nat fixes x :: real
assumes "c < x" "x < real (c + 1)"
shows "frac x > 0"
proof (rule ccontr, auto, goal_cases)
case 1
then obtain d :: int where d: "x = d" by (metis Ints_cases)
with assms have "c < d" "d < int c + 1" by auto
with int_intv_frac_gt0[OF this] 1 d show False by auto
qed
lemma nat_intv_frac_decomp:
fixes c :: nat and d :: real
assumes "c < d" "d < c + 1"
shows "d = c + frac d"
proof -
from assms have "int c = ⌊d⌋" by linarith
thus ?thesis by (simp add: frac_def)
qed
lemma nat_intv_not_int:
fixes c :: nat
assumes "real c < d" "d < c + 1"
shows "d ∉ ℤ"
proof (standard, goal_cases)
case 1
then obtain k :: int where "d = k" using Ints_cases by auto
then have "frac d = 0" by auto
moreover from nat_intv_frac_decomp[OF assms] have *: "d = c + frac d" by auto
ultimately have "d = c" by linarith
with assms show ?case by auto
qed
lemma frac_idempotent: "frac (frac x) = frac x" by (simp add: frac_eq frac_lt_1)
lemma frac_nat_add_id: "frac ((n :: nat) + (r :: real)) = frac r"
proof -
have "⋀r. frac (r::real) < 1"
by (meson frac_lt_1)
then show ?thesis
by (simp add: floor_add frac_def)
qed
lemma floor_nat_add_id: "0 ≤ (r :: real) ⟹ r < 1 ⟹ floor (real (n::nat) + r) = n" by linarith
lemma int_intv_frac_gt_0':
"(a :: real) ∈ ℤ ⟹ (b :: real) ∈ ℤ ⟹ a ≤ b ⟹ a ≠ b ⟹ a ≤ b - 1"
proof (goal_cases)
case 1
then have "a < b" by auto
from 1(1,2) obtain k l :: int where "a = real_of_int k" "b = real_of_int l" by (metis Ints_cases)
with ‹a < b› show ?case by auto
qed
lemma int_lt_Suc_le:
"(a :: real) ∈ ℤ ⟹ (b :: real) ∈ ℤ ⟹ a < b + 1 ⟹ a ≤ b"
proof (goal_cases)
case 1
from 1(1,2) obtain k l :: int where "a = real_of_int k" "b = real_of_int l" by (metis Ints_cases)
with ‹a < b + 1› show ?case by auto
qed
lemma int_lt_neq_Suc_lt:
"(a :: real) ∈ ℤ ⟹ (b :: real) ∈ ℤ ⟹ a < b ⟹ a + 1 ≠ b ⟹ a + 1 < b"
proof (goal_cases)
case 1
from 1(1,2) obtain k l :: int where "a = real_of_int k" "b = real_of_int l" by (metis Ints_cases)
with 1 show ?case by auto
qed
lemma int_lt_neq_prev_lt:
"(a :: real) ∈ ℤ ⟹ (b :: real) ∈ ℤ ⟹ a - 1 < b ⟹ a ≠ b ⟹ a < b"
proof (goal_cases)
case 1
from 1(1,2) obtain k l :: int where "a = real_of_int k" "b = real_of_int l" by (metis Ints_cases)
with 1 show ?case by auto
qed
lemma ints_le_add_frac1:
fixes a b x :: real
assumes "0 < x" "x < 1" "a ∈ ℤ" "b ∈ ℤ" "a + x ≤ b"
shows "a ≤ b"
using assms by auto
lemma ints_le_add_frac2:
fixes a b x :: real
assumes "0 ≤ x" "x < 1" "a ∈ ℤ" "b ∈ ℤ" "b ≤ a + x"
shows "b ≤ a"
using assms
by (metis add.commute add_le_cancel_left add_mono_thms_linordered_semiring(1) int_lt_Suc_le leD le_less_linear)
section ‹Ordering Fractions›
lemma distinct_twice_contradiction:
"xs ! i = x ⟹ xs ! j = x ⟹ i < j ⟹ j < length xs ⟹ ¬ distinct xs"
proof (rule ccontr, simp, induction xs arbitrary: i j)
case Nil thus ?case by auto
next
case (Cons y xs)
show ?case
proof (cases "i = 0")
case True
with Cons have "y = x" by auto
moreover from True Cons have "x ∈ set xs" by auto
ultimately show False using Cons(6) by auto
next
case False
with Cons have
"xs ! (i - 1) = x" "xs ! (j - 1) = x" "i - 1 < j - 1" "j - 1 < length xs" "distinct xs"
by auto
from Cons.IH[OF this] show False .
qed
qed
lemma distinct_nth_unique:
"xs ! i = xs ! j ⟹ i < length xs ⟹ j < length xs ⟹ distinct xs ⟹ i = j"
apply (rule ccontr)
apply (cases "i < j")
apply auto
apply (auto dest: distinct_twice_contradiction)
using distinct_twice_contradiction by fastforce
lemma (in linorder) linorder_order_fun:
fixes S :: "'a set"
assumes "finite S"
obtains f :: "'a ⇒ nat"
where "(∀ x ∈ S. ∀ y ∈ S. f x ≤ f y ⟷ x ≤ y)" and "range f ⊆ {0..card S - 1}"
proof -
obtain l where l_def: "l = sorted_list_of_set S" by auto
with assms have l: "set l = S" "sorted l" "distinct l" by auto
from l(1,3) ‹finite S› have len: "length l = card S" using distinct_card by force
let ?f = "λ x. if x ∉ S then 0 else THE i. i < length l ∧ l ! i = x"
{ fix x y assume A: "x ∈ S" "y ∈ S" "x < y"
with l(1) obtain i j where *: "l ! i = x" "l ! j = y" "i < length l" "j < length l"
by (meson in_set_conv_nth)
have "i < j"
proof (rule ccontr, goal_cases)
case 1
with sorted_nth_mono[OF l(2)] ‹i < length l› have "l ! j ≤ l ! i" by auto
with * A(3) show False by auto
qed
moreover have "?f x = i" using * l(3) A(1) by (auto) (rule, auto intro: distinct_nth_unique)
moreover have "?f y = j" using * l(3) A(2) by (auto) (rule, auto intro: distinct_nth_unique)
ultimately have "?f x < ?f y" by auto
} moreover
{ fix x y assume A: "x ∈ S" "y ∈ S" "?f x < ?f y"
with l(1) obtain i j where *: "l ! i = x" "l ! j = y" "i < length l" "j < length l"
by (meson in_set_conv_nth)
moreover have "?f x = i" using * l(3) A(1) by (auto) (rule, auto intro: distinct_nth_unique)
moreover have "?f y = j" using * l(3) A(2) by (auto) (rule, auto intro: distinct_nth_unique)
ultimately have **: "l ! ?f x = x" "l ! ?f y = y" "i < j" using A(3) by auto
have "x < y"
proof (rule ccontr, goal_cases)
case 1
then have "y ≤ x" by simp
moreover from sorted_nth_mono[OF l(2), of i j] **(3) * have "x ≤ y" by auto
ultimately show False using distinct_nth_unique[OF _ *(3,4) l(3)] *(1,2) **(3) by fastforce
qed
}
ultimately have "∀ x ∈ S. ∀ y ∈ S. ?f x ≤ ?f y ⟷ x ≤ y" by force
moreover have "range ?f ⊆ {0..card S - 1}"
proof (auto, goal_cases)
case (1 x)
with l(1) obtain i where *: "l ! i = x" "i < length l" by (meson in_set_conv_nth)
then have "?f x = i" using l(3) 1 by (auto) (rule, auto intro: distinct_nth_unique)
with len show ?case using *(2) 1 by auto
qed
ultimately show ?thesis ..
qed
locale enumerateable =
fixes T :: "'a set"
fixes less :: "'a ⇒ 'a ⇒ bool" (infix "≺" 50)
assumes finite: "finite T"
assumes total: "∀ x ∈ T. ∀ y ∈ T. x ≠ y ⟶ (x ≺ y) ∨ (y ≺ x)"
assumes trans: "∀x ∈ T. ∀ y ∈ T. ∀ z ∈ T. (x :: 'a) ≺ y ⟶ y ≺ z ⟶ x ≺ z"
assumes asymmetric: "∀ x ∈ T. ∀ y ∈ T. x ≺ y ⟶ ¬ (y ≺ x)"
begin
lemma non_empty_set_has_least':
"S ⊆ T ⟹ S ≠ {} ⟹ ∃ x ∈ S. ∀ y ∈ S. x ≠ y ⟶ ¬ y ≺ x"
proof (rule ccontr, induction "card S" arbitrary: S)
case 0 then show ?case using finite by (auto simp: finite_subset)
next
case (Suc n)
then obtain x where x: "x ∈ S" by blast
from finite Suc.prems(1) have finite: "finite S" by (auto simp: finite_subset)
let ?S = "S - {x}"
show ?case
proof (cases "S = {x}")
case True
with Suc.prems(3) show False by auto
next
case False
then have S: "?S ≠ {}" using x by blast
show False
proof (cases "∃x ∈ ?S. ∀y∈?S. x ≠ y ⟶ ¬ y ≺ x")
case False
have "n = card ?S" using Suc.hyps finite by (simp add: x)
from Suc.hyps(1)[OF this _ S False] Suc.prems(1) show False by auto
next
case True
then obtain x' where x': "∀y∈?S. x' ≠ y ⟶ ¬ y ≺ x'" "x' ∈ ?S" "x ≠ x'" by auto
from total Suc.prems(1) x'(2) have "⋀ y. y ∈ S ⟹ x' ≠ y ⟹ ¬ y ≺ x' ⟹ x' ≺ y" by auto
from total Suc.prems(1) x'(1,2) have *: "∀ y ∈ ?S. x' ≠ y ⟶ x' ≺ y" by auto
from Suc.prems(3) x'(1,2) have **: "x ≺ x'" by auto
have "∀ y ∈ ?S. x ≺ y"
proof
fix y assume y: "y ∈ S - {x}"
show "x ≺ y"
proof (cases "y = x'")
case True then show ?thesis using ** by simp
next
case False
with * y have "x' ≺ y" by auto
with trans Suc.prems(1) ** y x'(2) x ** show ?thesis by auto
qed
qed
with x Suc.prems(1,3) show False using asymmetric by blast
qed
qed
qed
lemma non_empty_set_has_least'':
"S ⊆ T ⟹ S ≠ {} ⟹ ∃! x ∈ S. ∀ y ∈ S. x ≠ y ⟶ ¬ y ≺ x"
proof (intro ex_ex1I, goal_cases)
case 1
with non_empty_set_has_least'[OF this] show ?case by auto
next
case (2 x y)
show ?case
proof (rule ccontr)
assume "x ≠ y"
with 2 total have "x ≺ y ∨ y ≺ x" by blast
with 2(2-) ‹x ≠ y› show False by auto
qed
qed
abbreviation "least S ≡ THE t :: 'a. t ∈ S ∧ (∀ y ∈ S. t ≠ y ⟶ ¬ y ≺ t)"
lemma non_empty_set_has_least:
"S ⊆ T ⟹ S ≠ {} ⟹ least S ∈ S ∧ (∀ y ∈ S. least S ≠ y ⟶ ¬ y ≺ least S)"
proof goal_cases
case 1
note A = this
show ?thesis
proof (rule theI', goal_cases)
case 1
from non_empty_set_has_least''[OF A] show ?case .
qed
qed
fun f :: "'a set ⇒ nat ⇒ 'a list"
where
"f S 0 = []" |
"f S (Suc n) = least S # f (S - {least S}) n"
inductive sorted :: "'a list ⇒ bool" where
Nil [iff]: "sorted []"
| Cons: "∀y∈set xs. x ≺ y ⟹ sorted xs ⟹ sorted (x # xs)"
lemma f_set:
"S ⊆ T ⟹ n = card S ⟹ set (f S n) = S"
proof (induction n arbitrary: S)
case 0 then show ?case using finite by (auto simp: finite_subset)
next
case (Suc n)
then have fin: "finite S" using finite by (auto simp: finite_subset)
with Suc.prems have "S ≠ {}" by auto
from non_empty_set_has_least[OF Suc.prems(1) this] have least: "least S ∈ S" by blast
let ?S = "S - {least S}"
from fin least Suc.prems have "?S ⊆ T" "n = card ?S" by auto
from Suc.IH[OF this] have "set (f ?S n) = ?S" .
with least show ?case by auto
qed
lemma f_distinct:
"S ⊆ T ⟹ n = card S ⟹ distinct (f S n)"
proof (induction n arbitrary: S)
case 0 then show ?case using finite by (auto simp: finite_subset)
next
case (Suc n)
then have fin: "finite S" using finite by (auto simp: finite_subset)
with Suc.prems have "S ≠ {}" by auto
from non_empty_set_has_least[OF Suc.prems(1) this] have least: "least S ∈ S" by blast
let ?S = "S - {least S}"
from fin least Suc.prems have "?S ⊆ T" "n = card ?S" by auto
from Suc.IH[OF this] f_set[OF this] have "distinct (f ?S n)" "set (f ?S n) = ?S" .
then show ?case by simp
qed
lemma f_sorted:
"S ⊆ T ⟹ n = card S ⟹ sorted (f S n)"
proof (induction n arbitrary: S)
case 0 then show ?case by auto
next
case (Suc n)
then have fin: "finite S" using finite by (auto simp: finite_subset)
with Suc.prems have "S ≠ {}" by auto
from non_empty_set_has_least[OF Suc.prems(1) this] have least:
"least S ∈ S" "(∀ y ∈ S. least S ≠ y ⟶ ¬ y ≺ least S)"
by blast+
let ?S = "S - {least S}"
{ fix x assume x: "x ∈ ?S"
with least have "¬ x ≺ least S" by auto
with total x Suc.prems(1) least(1) have "least S ≺ x" by blast
} note le = this
from fin least Suc.prems have "?S ⊆ T" "n = card ?S" by auto
from f_set[OF this] Suc.IH[OF this] have *: "set (f ?S n) = ?S" "sorted (f ?S n)" .
with le have "∀ x ∈ set (f ?S n). least S ≺ x" by auto
with *(2) show ?case by (auto intro: Cons)
qed
lemma sorted_nth_mono:
"sorted xs ⟹ i < j ⟹ j < length xs ⟹ xs!i ≺ xs!j"
proof (induction xs arbitrary: i j)
case Nil thus ?case by auto
next
case (Cons x xs)
show ?case
proof (cases "i = 0")
case True
with Cons.prems show ?thesis by (auto elim: sorted.cases)
next
case False
from Cons.prems have "sorted xs" by (auto elim: sorted.cases)
from Cons.IH[OF this] Cons.prems False show ?thesis by auto
qed
qed
lemma order_fun:
fixes S :: "'a set"
assumes "S ⊆ T"
obtains f :: "'a ⇒ nat" where "∀ x ∈ S. ∀ y ∈ S. f x < f y ⟷ x ≺ y" and "range f ⊆ {0..card S - 1}"
proof -
obtain l where l_def: "l = f S (card S)" by auto
with f_set f_distinct f_sorted assms have l: "set l = S" "sorted l" "distinct l" by auto
then have len: "length l = card S" using distinct_card by force
let ?f = "λ x. if x ∉ S then 0 else THE i. i < length l ∧ l ! i = x"
{ fix x y :: 'a assume A: "x ∈ S" "y ∈ S" "x ≺ y"
with l(1) obtain i j where *: "l ! i = x" "l ! j = y" "i < length l" "j < length l"
by (meson in_set_conv_nth)
have "i ≠ j"
proof (rule ccontr, goal_cases)
case 1
with A * have "x ≺ x" by auto
with asymmetric A assms show False by auto
qed
have "i < j"
proof (rule ccontr, goal_cases)
case 1
with ‹i ≠ j› sorted_nth_mono[OF l(2)] ‹i < length l› have "l ! j ≺ l ! i" by auto
with * A(3) A assms asymmetric show False by auto
qed
moreover have "?f x = i" using * l(3) A(1) by (auto) (rule, auto intro: distinct_nth_unique)
moreover have "?f y = j" using * l(3) A(2) by (auto) (rule, auto intro: distinct_nth_unique)
ultimately have "?f x < ?f y" by auto
} moreover
{ fix x y assume A: "x ∈ S" "y ∈ S" "?f x < ?f y"
with l(1) obtain i j where *: "l ! i = x" "l ! j = y" "i < length l" "j < length l"
by (meson in_set_conv_nth)
moreover have "?f x = i" using * l(3) A(1) by (auto) (rule, auto intro: distinct_nth_unique)
moreover have "?f y = j" using * l(3) A(2) by (auto) (rule, auto intro: distinct_nth_unique)
ultimately have **: "l ! ?f x = x" "l ! ?f y = y" "i < j" using A(3) by auto
from sorted_nth_mono[OF l(2), of i j] **(3) * have "x ≺ y" by auto
}
ultimately have "∀ x ∈ S. ∀ y ∈ S. ?f x < ?f y ⟷ x ≺ y" by force
moreover have "range ?f ⊆ {0..card S - 1}"
proof (auto, goal_cases)
case (1 x)
with l(1) obtain i where *: "l ! i = x" "i < length l" by (meson in_set_conv_nth)
then have "?f x = i" using l(3) 1 by (auto) (rule, auto intro: distinct_nth_unique)
with len show ?case using *(2) 1 by auto
qed
ultimately show ?thesis ..
qed
end
lemma finite_total_preorder_enumeration:
fixes X :: "'a set"
fixes r :: "'a rel"
assumes fin: "finite X"
assumes tot: "total_on X r"
assumes refl: "refl_on X r"
assumes trans: "trans r"
obtains f :: "'a ⇒ nat" where "∀ x ∈ X. ∀ y ∈ X. f x ≤ f y ⟷ (x, y) ∈ r"
proof -
let ?A = "λ x. {y ∈ X . (y, x) ∈ r ∧ (x, y) ∈ r}"
have ex: "∀ x ∈ X. x ∈ ?A x" using refl unfolding refl_on_def by auto
let ?R = "λ S. SOME y. y ∈ S"
let ?T = "{?A x | x. x ∈ X}"
{ fix A assume A: "A ∈ ?T"
then obtain x where x: "x ∈ X" "?A x = A" by auto
then have "x ∈ A" using refl unfolding refl_on_def by auto
then have "?R A ∈ A" by (auto intro: someI)
with x(2) have "(?R A, x) ∈ r" "(x, ?R A) ∈ r" by auto
with trans have "(?R A, ?R A) ∈ r" unfolding trans_def by blast
} note refl_lifted = this
{ fix A assume A: "A ∈ ?T"
then obtain x where x: "x ∈ X" "?A x = A" by auto
then have "x ∈ A" using refl unfolding refl_on_def by auto
then have "?R A ∈ A" by (auto intro: someI)
} note R_in = this
{ fix A y z assume A: "A ∈ ?T" and y: "y ∈ A" and z: "z ∈ A"
from A obtain x where x: "x ∈ X" "?A x = A" by auto
then have "x ∈ A" using refl unfolding refl_on_def by auto
with x y have "(x, y) ∈ r" "(y, x) ∈ r" by auto
moreover from x z have "(x,z) ∈ r" "(z,x) ∈ r" by auto
ultimately have "(y, z) ∈ r" "(z, y) ∈ r" using trans unfolding trans_def by blast+
} note A_dest' = this
{ fix A y assume "A ∈ ?T" and "y ∈ A"
with A_dest'[OF _ _ R_in] have "(?R A, y) ∈ r" "(y, ?R A) ∈ r" by blast+
} note A_dest = this
{ fix A y z assume A: "A ∈ ?T" and y: "y ∈ A" and z: "z ∈ X" and r: "(y, z) ∈ r" "(z, y) ∈ r"
from A obtain x where x: "x ∈ X" "?A x = A" by auto
then have "x ∈ A" using refl unfolding refl_on_def by auto
with x y have "(x,y) ∈ r" "(y, x) ∈ r" by auto
with r have "(x,z) ∈ r" "(z,x) ∈ r" using trans unfolding trans_def by blast+
with x z have "z ∈ A" by auto
} note A_intro' = this
{ fix A y assume A: "A ∈ ?T" and y: "y ∈ X" and r: "(?R A, y) ∈ r" "(y, ?R A) ∈ r"
with A_intro' R_in have "y ∈ A" by blast
} note A_intro = this
{ fix A B C
assume r1: "(?R A, ?R B) ∈ r" and r2: "(?R B, ?R C) ∈ r"
with trans have "(?R A, ?R C) ∈ r" unfolding trans_def by blast
} note trans_lifted[intro] = this
{ fix A B a b
assume A: "A ∈ ?T" and B: "B ∈ ?T"
and a: "a ∈ A" and b: "b ∈ B"
and r: "(a, b) ∈ r" "(b, a) ∈ r"
with R_in have "?R A ∈ A" "?R B ∈ B" by blast+
have "A = B"
proof auto
fix x assume x: "x ∈ A"
with A have "x ∈ X" by auto
from A_intro'[OF B b this] A_dest'[OF A x a] r trans[unfolded trans_def] show "x ∈ B" by blast
next
fix x assume x: "x ∈ B"
with B have "x ∈ X" by auto
from A_intro'[OF A a this] A_dest'[OF B x b] r trans[unfolded trans_def] show "x ∈ A" by blast
qed
} note eq_lifted'' = this
{ fix A B C
assume A: "A ∈ ?T" and B: "B ∈ ?T" and r: "(?R A, ?R B) ∈ r" "(?R B, ?R A) ∈ r"
with eq_lifted'' R_in have "A = B" by blast
} note eq_lifted' = this
{ fix A B C
assume A: "A ∈ ?T" and B: "B ∈ ?T" and eq: "?R A = ?R B"
from R_in[OF A] A have "?R A ∈ X" by auto
with refl have "(?R A, ?R A) ∈ r" unfolding refl_on_def by auto
with eq_lifted'[OF A B] eq have "A = B" by auto
} note eq_lifted = this
{ fix A B
assume A: "A ∈ ?T" and B: "B ∈ ?T" and neq: "A ≠ B"
from neq eq_lifted[OF A B] have "?R A ≠ ?R B" by metis
moreover from A B R_in have "?R A ∈ X" "?R B ∈ X" by auto
ultimately have "(?R A, ?R B) ∈ r ∨ (?R B, ?R A) ∈ r" using tot unfolding total_on_def by auto
} note total_lifted = this
{ fix x y assume x: "x ∈ X" and y: "y ∈ X"
from x y have "?A x ∈ ?T" "?A y ∈ ?T" by auto
from R_in[OF this(1)] R_in[OF this(2)] have "?R (?A x) ∈ ?A x" "?R (?A y) ∈ ?A y" by auto
then have "(x, ?R (?A x)) ∈ r" "(?R (?A y), y) ∈ r" "(?R (?A x), x) ∈ r" "(y, ?R (?A y)) ∈ r" by auto
with trans[unfolded trans_def] have "(x, y) ∈ r ⟷ (?R (?A x), ?R (?A y)) ∈ r" by meson
} note repr = this
interpret interp: enumerateable "{?A x | x. x ∈ X}" "λ A B. A ≠ B ∧ (?R A, ?R B) ∈ r"
proof (standard, goal_cases)
case 1
from fin show ?case by auto
next
case 2
with total_lifted show ?case by auto
next
case 3
then show ?case unfolding transp_def
proof (standard, standard, standard, standard, standard, goal_cases)
case (1 A B C)
note A = this
with trans_lifted have "(?R A,?R C) ∈ r" by blast
moreover have "A ≠ C"
proof (rule ccontr, goal_cases)
case 1
with A have "(?R A,?R B) ∈ r" "(?R B,?R A) ∈ r" by auto
with eq_lifted'[OF A(1,2)] A show False by auto
qed
ultimately show ?case by auto
qed
next
case 4
{ fix A B assume A: "A ∈ ?T" and B: "B ∈ ?T" and neq: "A ≠ B" "(?R A, ?R B) ∈ r"
with eq_lifted'[OF A B] neq have "¬ (?R B, ?R A) ∈ r" by auto
}
then show ?case by auto
qed
from interp.order_fun[OF subset_refl] obtain f :: "'a set ⇒ nat" where
f: "∀ x ∈ ?T. ∀ y ∈ ?T. f x < f y ⟷ x ≠ y ∧ (?R x, ?R y) ∈ r" "range f ⊆ {0..card ?T - 1}"
by auto
let ?f = "λ x. if x ∈ X then f (?A x) else 0"
{ fix x y assume x: "x ∈ X" and y: "y ∈ X"
have "?f x ≤ ?f y ⟷ (x, y) ∈ r"
proof (cases "x = y")
case True
with refl x show ?thesis unfolding refl_on_def by auto
next
case False
note F = this
from ex x y have *: "?A x ∈ ?T" "?A y ∈ ?T" "x ∈ ?A x" "y ∈ ?A y" by auto
show ?thesis
proof (cases "(x, y) ∈ r ∧ (y, x) ∈ r")
case True
from eq_lifted''[OF *] True x y have "?f x = ?f y" by auto
with True show ?thesis by auto
next
case False
with A_dest'[OF *(1,3), of y] *(4) have **: "?A x ≠ ?A y" by auto
from total_lifted[OF *(1,2) this] have "(?R (?A x), ?R (?A y)) ∈ r ∨ (?R (?A y), ?R (?A x)) ∈ r" .
then have neq: "?f x ≠ ?f y"
proof (standard, goal_cases)
case 1
with f *(1,2) ** have "f (?A x) < f (?A y)" by auto
with * show ?case by auto
next
case 2
with f *(1,2) ** have "f (?A y) < f (?A x)" by auto
with * show ?case by auto
qed
then have "?thesis = (?f x < ?f y ⟷ (x, y) ∈ r)" by linarith
moreover from f ** * have "(?f x < ?f y ⟷ (?R (?A x), ?R (?A y)) ∈ r)" by auto
moreover from repr * have "… ⟷ (x, y) ∈ r" by auto
ultimately show ?thesis by auto
qed
qed
}
then have "∀ x ∈ X. ∀ y ∈ X. ?f x ≤ ?f y ⟷ (x, y) ∈ r" by blast
then show ?thesis ..
qed
section ‹Finiteness›
lemma pairwise_finiteI:
assumes "finite {b. ∃a. P a b}" (is "finite ?B")
assumes "finite {a. ∃b. P a b}"
shows "finite {(a,b). P a b}" (is "finite ?C")
proof -
from assms(1) have "finite ?B" .
let ?f = "λ b. {(a,b) | a. P a b}"
{ fix b
have "?f b ⊆ {(a,b) | a. ∃b. P a b}" by blast
moreover have "finite …" using assms(2) by auto
ultimately have "finite (?f b)" by (blast intro: finite_subset)
}
with assms(1) have "finite (⋃ (?f ` ?B))" by auto
moreover have "?C ⊆ ⋃ (?f ` ?B)" by auto
ultimately show ?thesis by (blast intro: finite_subset)
qed
lemma finite_ex_and1:
assumes "finite {b. ∃a. P a b}" (is "finite ?A")
shows "finite {b. ∃a. P a b ∧ Q a b}" (is "finite ?B")
proof -
have "?B ⊆ ?A" by auto
with assms show ?thesis by (blast intro: finite_subset)
qed
lemma finite_ex_and2:
assumes "finite {b. ∃a. Q a b}" (is "finite ?A")
shows "finite {b. ∃a. P a b ∧ Q a b}" (is "finite ?B")
proof -
have "?B ⊆ ?A" by auto
with assms show ?thesis by (blast intro: finite_subset)
qed
lemma finite_set_of_finite_funs2:
fixes A :: "'a set"
and B :: "'b set"
and C :: "'c set"
and d :: "'c"
assumes "finite A"
and "finite B"
and "finite C"
shows "finite {f. ∀x. ∀y. (x ∈ A ∧ y ∈ B ⟶ f x y ∈ C) ∧ (x ∉ A ⟶ f x y = d) ∧ (y ∉ B ⟶ f x y = d)}"
proof -
let ?S = "{f. ∀x. ∀y. (x ∈ A ∧ y ∈ B ⟶ f x y ∈ C) ∧ (x ∉ A ⟶ f x y = d) ∧ (y ∉ B ⟶ f x y = d)}"
let ?R = "{g. ∀x. (x ∈ B ⟶ g x ∈ C) ∧ (x ∉ B ⟶ g x = d)}"
let ?Q = "{f. ∀x. (x ∈ A ⟶ f x ∈ ?R) ∧ (x ∉ A ⟶ f x = (λy. d))}"
from finite_set_of_finite_funs[OF assms(2,3)] have "finite ?R" .
from finite_set_of_finite_funs[OF assms(1) this, of "λ y. d"] have "finite ?Q" .
moreover have "?S = ?Q" by auto (case_tac "xa ∈ A", auto)
ultimately show ?thesis by simp
qed
section ‹Numbering the elements of finite sets›
lemma upt_last_append: "a ≤ b ⟹ [a..<b] @ [b] = [a ..< Suc b]" by (induction b) auto
lemma map_of_zip_dom_to_range:
"a ∈ set A ⟹ length B = length A ⟹ the (map_of (zip A B) a) ∈ set B"
by (metis map_of_SomeD map_of_zip_is_None option.collapse set_zip_rightD)
lemma zip_range_id:
"length A = length B ⟹ snd ` set (zip A B) = set B"
by (metis map_snd_zip set_map)
lemma map_of_zip_in_range:
"distinct A ⟹ length B = length A ⟹ b ∈ set B ⟹ ∃ a ∈ set A. the (map_of (zip A B) a) = b"
proof goal_cases
case 1
from ran_distinct[of "zip A B"] 1(1,2) have
"ran (map_of (zip A B)) = set B"
by (auto simp: zip_range_id)
with 1(3) obtain a where "map_of (zip A B) a = Some b" unfolding ran_def by auto
with map_of_zip_is_Some[OF 1(2)[symmetric]] have "the (map_of (zip A B) a) = b" "a ∈ set A" by auto
then show ?case by blast
qed
lemma distinct_zip_inj:
"distinct ys ⟹ (a, b) ∈ set (zip xs ys) ⟹ (c, b) ∈ set (zip xs ys) ⟹ a = c"
proof (induction ys arbitrary: xs)
case Nil then show ?case by auto
next
case (Cons y ys)
from this(3) have "xs ≠ []" by auto
then obtain z zs where xs: "xs = z # zs" by (cases xs) auto
show ?case
proof (cases "(a, b) ∈ set (zip zs ys)")
case True
note T = this
then have b: "b ∈ set ys" by (meson in_set_zipE)
show ?thesis
proof (cases "(c, b) ∈ set (zip zs ys)")
case True
with T Cons show ?thesis by auto
next
case False
with Cons.prems xs b show ?thesis by auto
qed
next
case False
with Cons.prems xs have b: "a = z" "b = y" by auto
show ?thesis
proof (cases "(c, b) ∈ set (zip zs ys)")
case True
then have "b ∈ set ys" by (meson in_set_zipE)
with b ‹distinct (y#ys)› show ?thesis by auto
next
case False
with Cons.prems xs b show ?thesis by auto
qed
qed
qed
lemma map_of_zip_distinct_inj:
"distinct B ⟹ length A = length B ⟹ inj_on (the o map_of (zip A B)) (set A)"
unfolding inj_on_def proof (clarify, goal_cases)
case (1 x y)
with map_of_zip_is_Some[OF 1(2)] obtain a where
"map_of (zip A B) x = Some a" "map_of (zip A B) y = Some a"
by auto
then have "(x, a) ∈ set (zip A B)" "(y, a) ∈ set (zip A B)" using map_of_SomeD by metis+
from distinct_zip_inj[OF _ this] 1 show ?case by auto
qed
lemma nat_not_ge_1D: "¬ Suc 0 ≤ x ⟹ x = 0" by auto
lemma standard_numbering:
assumes "finite A"
obtains v :: "'a ⇒ nat" and n where "bij_betw v A {1..n}"
and "∀ c ∈ A. v c > 0"
and "∀ c. c ∉ A ⟶ v c > n"
proof -
from assms obtain L where L: "distinct L" "set L = A" by (meson finite_distinct_list)
let ?N = "length L + 1"
let ?P = "zip L [1..<?N]"
let ?v = "λ x. let v = map_of ?P x in if v = None then ?N else the v"
from length_upt have len: "length [1..<?N] = length L" by auto (cases L, auto)
then have lsimp: "length [Suc 0 ..<Suc (length L)] = length L" by simp
note * = map_of_zip_dom_to_range[OF _ len]
have "bij_betw ?v A {1..length L}" unfolding bij_betw_def
proof
show "?v ` A = {1..length L}" apply auto
apply (auto simp: L)[]
apply (auto simp only: upt_last_append)[] using * apply force
using * apply (simp only: upt_last_append) apply force
apply (simp only: upt_last_append) using L(2) apply (auto dest: nat_not_ge_1D)
apply (subgoal_tac "x ∈ set [1..< length L +1]")
apply (force dest!: map_of_zip_in_range[OF L(1) len])
apply auto
done
next
from L map_of_zip_distinct_inj[OF distinct_upt, of L 1 "length L + 1"] len
have "inj_on (the o map_of ?P) A" by auto
moreover have "inj_on (the o map_of ?P) A = inj_on ?v A"
using len L(2) by - (rule inj_on_cong, auto)
ultimately show "inj_on ?v A" by blast
qed
moreover have "∀ c ∈ A. ?v c > 0"
proof
fix c
show "?v c > 0"
proof (cases "c ∈ set L")
case False
then show ?thesis by auto
next
case True
with dom_map_of_zip[OF len[symmetric]] obtain x where
"Some x = map_of ?P c" "x ∈ set [1..<length L + 1]"
by (metis * domIff option.collapse)
then have "?v c ∈ set [1..<length L + 1]" using * True len by auto
then show ?thesis by auto
qed
qed
moreover have "∀ c. c ∉ A ⟶ ?v c > length L" using L by auto
ultimately show ?thesis ..
qed
end