Theory Buffer
section ‹Refining a Buffer Specification›
theory Buffer
imports State
begin
text ‹
We specify a simple FIFO buffer and prove that two FIFO buffers
in a row implement a FIFO buffer.
›
subsection "Buffer specification"
text ‹
The following definitions all take three parameters: a state function
representing the input channel of the FIFO buffer, another representing
the internal queue, and a third one representing the output channel.
These parameters will be instantiated later in the definition of the
double FIFO.
›
definition BInit :: "'a statefun ⇒ 'a list statefun ⇒ 'a statefun ⇒ temporal"
where "BInit ic q oc ≡ TEMP $q = #[]
∧ $ic = $oc"
definition Enq :: "'a statefun ⇒ 'a list statefun ⇒ 'a statefun ⇒ temporal"
where "Enq ic q oc ≡ TEMP ic$ ≠ $ic
∧ q$ = $q @ [ ic$ ]
∧ oc$ = $oc"
definition Deq :: "'a statefun ⇒ 'a list statefun ⇒ 'a statefun ⇒ temporal"
where "Deq ic q oc ≡ TEMP # 0 < length<$q>
∧ oc$ = hd<$q>
∧ q$ = tl<$q>
∧ ic$ = $ic"
definition Nxt :: "'a statefun ⇒ 'a list statefun ⇒ 'a statefun ⇒ temporal"
where "Nxt ic q oc ≡ TEMP (Enq ic q oc ∨ Deq ic q oc)"
definition ISpec :: "'a statefun ⇒ 'a list statefun ⇒ 'a statefun ⇒ temporal"
where "ISpec ic q oc ≡ TEMP BInit ic q oc
∧ □[Nxt ic q oc]_(ic,q,oc)
∧ WF(Deq ic q oc)_(ic,q,oc)"
definition Spec :: "'a statefun ⇒ 'a statefun ⇒ temporal"
where "Spec ic oc == TEMP (∃∃ q. ISpec ic q oc)"
subsection "Properties of the buffer"
text ‹
The buffer never enqueues the same element twice. We therefore
have the following invariant:
\begin{itemize}
\item any two subsequent elements in the queue are different, and
the last element in the queue is different from the value of the
output channel,
\item if the queue is non-empty then the last element in the queue
is the value that appears on the input channel,
\item if the queue is empty then the values on the output and input
channels are equal.
\end{itemize}
The following auxiliary predicate ‹noreps› is true if no
two subsequent elements in a list are identical.
›
definition noreps :: "'a list ⇒ bool"
where "noreps xs ≡ ∀i < length xs - 1. xs!i ≠ xs!(Suc i)"
definition BInv :: "'a statefun ⇒ 'a list statefun ⇒ 'a statefun ⇒ temporal"
where "BInv ic q oc ≡ TEMP List.last<$oc # $q> = $ic ∧ noreps<$oc # $q>"
lemmas buffer_defs = BInit_def Enq_def Deq_def Nxt_def
ISpec_def Spec_def BInv_def
lemma ISpec_stutinv: "STUTINV (ISpec ic q oc)"
unfolding buffer_defs by (simp add: bothstutinvs livestutinv)
lemma Spec_stutinv: "STUTINV Spec ic oc"
unfolding buffer_defs by (simp add: bothstutinvs livestutinv eexSTUT)
text ‹A lemma about lists that is useful in the following›
lemma tl_self_iff_empty[simp]: "(tl xs = xs) = (xs = [])"
proof
assume 1: "tl xs = xs"
show "xs = []"
proof (rule ccontr)
assume "xs ≠ []" with 1 show "False"
by (auto simp: neq_Nil_conv)
qed
qed (auto)
lemma tl_self_iff_empty'[simp]: "(xs = tl xs) = (xs = [])"
proof
assume 1: "xs = tl xs"
show "xs = []"
proof (rule ccontr)
assume "xs ≠ []" with 1 show "False"
by (auto simp: neq_Nil_conv)
qed
qed (auto)
lemma Deq_visible:
assumes v: "⊢ Unchanged v ⟶ Unchanged q"
shows "|~ <Deq ic q oc>_v = Deq ic q oc"
proof (auto simp: tla_defs)
fix w
assume deq: "w ⊨ Deq ic q oc" and unch: "v (w (Suc 0)) = v (w 0)"
from unch v[unlifted] have "q (w (Suc 0)) = q (w 0)"
by (auto simp: tla_defs)
with deq show "False" by (auto simp: Deq_def tla_defs)
qed
lemma Deq_enabledE: "⊢ Enabled <Deq ic q oc>_(ic,q,oc) ⟶ $q ~= #[]"
by (auto elim!: enabledE simp: Deq_def tla_defs)
text ‹
We now prove that ‹BInv› is an invariant of the Buffer
specification.
We need several lemmas about ‹noreps› that are used in the
invariant proof.
›
lemma noreps_empty [simp]: "noreps []"
by (auto simp: noreps_def)
lemma noreps_singleton: "noreps [x]"
by (auto simp: noreps_def)
lemma noreps_cons [simp]:
"noreps (x # xs) = (noreps xs ∧ (xs = [] ∨ x ≠ hd xs))"
proof (auto simp: noreps_singleton)
assume cons: "noreps (x # xs)"
show "noreps xs"
proof (auto simp: noreps_def)
fix i
assume i: "i < length xs - Suc 0" and eq: "xs!i = xs!(Suc i)"
from i have "Suc i < length (x#xs) - 1" by auto
moreover
from eq have "(x#xs)!(Suc i) = (x#xs)!(Suc (Suc i))" by auto
moreover
note cons
ultimately show False by (auto simp: noreps_def)
qed
next
assume 1: "noreps (hd xs # xs)" and 2: "xs ≠ []"
from 2 obtain x xxs where "xs = x # xxs" by (cases xs, auto)
with 1 show False by (auto simp: noreps_def)
next
assume 1: "noreps xs" and 2: "x ≠ hd xs"
show "noreps (x # xs)"
proof (auto simp: noreps_def)
fix i
assume i: "i < length xs" and eq: "(x # xs)!i = xs!i"
from i obtain y ys where xs: "xs = y # ys" by (cases xs, auto)
show False
proof (cases i)
assume "i = 0"
with eq 2 xs show False by auto
next
fix k
assume k: "i = Suc k"
with i eq xs 1 show False by (auto simp: noreps_def)
qed
qed
qed
lemma noreps_append [simp]:
"noreps (xs @ ys) =
(noreps xs ∧ noreps ys ∧ (xs = [] ∨ ys = [] ∨ List.last xs ≠ hd ys))"
proof auto
assume 1: "noreps (xs @ ys)"
show "noreps xs"
proof (auto simp: noreps_def)
fix i
assume i: "i < length xs - Suc 0" and eq: "xs!i = xs!(Suc i)"
from i have "i < length (xs @ ys) - Suc 0" by auto
moreover
from i eq have "(xs @ ys)!i = (xs@ys)!(Suc i)" by (auto simp: nth_append)
moreover note 1
ultimately show "False" by (auto simp: noreps_def)
qed
next
assume 1: "noreps (xs @ ys)"
show "noreps ys"
proof (auto simp: noreps_def)
fix i
assume i: "i < length ys - Suc 0" and eq: "ys!i = ys!(Suc i)"
from i have "i + length xs < length (xs @ ys) - Suc 0" by auto
moreover
from i eq have "(xs @ ys)!(i+length xs) = (xs@ys)!(Suc (i + length xs))"
by (auto simp: nth_append)
moreover note 1
ultimately show "False" by (auto simp: noreps_def)
qed
next
assume 1: "noreps (xs @ ys)" and 2: "xs ≠ []" and 3: "ys ≠ []"
and 4: "List.last xs = hd ys"
from 2 obtain x xxs where xs: "xs = x # xxs" by (cases xs, auto)
from 3 obtain y yys where ys: "ys = y # yys" by (cases ys, auto)
from xs ys have 5: "length xxs < length (xs @ ys) - 1" by auto
from 4 xs ys have "(xs @ ys) ! (length xxs) = (xs @ ys) ! (Suc (length xxs))"
by (auto simp: nth_append last_conv_nth)
with 5 1 show "False" by (auto simp: noreps_def)
next
assume 1: "noreps xs" and 2: "noreps ys" and 3: "List.last xs ≠ hd ys"
show "noreps (xs @ ys)"
proof (cases "xs = [] ∨ ys = []")
case True
with 1 2 show ?thesis by auto
next
case False
then obtain x xxs where xs: "xs = x # xxs" by (cases xs, auto)
from False obtain y yys where ys: "ys = y # yys" by (cases ys, auto)
show ?thesis
proof (auto simp: noreps_def)
fix i
assume i: "i < length xs + length ys - Suc 0"
and eq: "(xs @ ys)!i = (xs @ ys)!(Suc i)"
show "False"
proof (cases "i < length xxs")
case True
hence "i < length (x # xxs)" by simp
hence xsi: "((x # xxs) @ ys)!i = (x # xxs)!i"
unfolding nth_append by simp
from True have "(xxs @ ys)!i = xxs!i" by (auto simp: nth_append)
with True xsi eq 1 xs show "False" by (auto simp: noreps_def)
next
assume i2: "¬(i < length xxs)"
show False
proof (cases "i = length xxs")
case True
with xs have xsi: "(xs @ ys)!i = List.last xs"
by (auto simp: nth_append last_conv_nth)
from True xs ys have "(xs @ ys)!(Suc i) = y"
by (auto simp: nth_append)
with 3 ys eq xsi show False by simp
next
case False
with i2 xs have xsi: "¬(i < length xs)" by auto
hence "(xs @ ys)!i = ys!(i - length xs)"
by (simp add: nth_append)
moreover
from xsi have "Suc i - length xs = Suc (i - length xs)" by auto
with xsi have "(xs @ ys)!(Suc i) = ys!(Suc (i - length xs))"
by (simp add: nth_append)
moreover
from i xsi have "i - length xs < length ys - 1" by auto
with 2 have "ys!(i - length xs) ≠ ys!(Suc (i - length xs))"
by (auto simp: noreps_def)
moreover
note eq
ultimately show False by simp
qed
qed
qed
qed
qed
lemma ISpec_BInv_lemma:
"⊢ BInit ic q oc ∧ □[Nxt ic q oc]_(ic,q,oc) ⟶ □(BInv ic q oc)"
proof (rule invmono)
show "⊢ BInit ic q oc ⟶ BInv ic q oc"
by (auto simp: BInit_def BInv_def)
next
have enq: "|~ Enq ic q oc ⟶ BInv ic q oc ⟶ ○(BInv ic q oc)"
by (auto simp: Enq_def BInv_def tla_defs)
have deq: "|~ Deq ic q oc ⟶ BInv ic q oc ⟶ ○(BInv ic q oc)"
by (auto simp: Deq_def BInv_def tla_defs neq_Nil_conv)
have unch: "|~ Unchanged (ic,q,oc) ⟶ BInv ic q oc ⟶ ○(BInv ic q oc)"
by (auto simp: BInv_def tla_defs)
show "|~ BInv ic q oc ∧ [Nxt ic q oc]_(ic, q, oc) ⟶ ○(BInv ic q oc)"
by (auto simp: Nxt_def actrans_def
elim: enq[unlift_rule] deq[unlift_rule] unch[unlift_rule])
qed
theorem ISpec_BInv: "⊢ ISpec ic q oc ⟶ □(BInv ic q oc)"
by (auto simp: ISpec_def intro: ISpec_BInv_lemma[unlift_rule])
subsection "Two FIFO buffers in a row implement a buffer"
locale DBuffer =
fixes inp :: "'a statefun"
and mid :: "'a statefun"
and out :: "'a statefun"
and q1 :: "'a list statefun"
and q2 :: "'a list statefun"
and vars
defines "vars ≡ LIFT (inp,mid,out,q1,q2)"
assumes DB_base: "basevars vars"
begin
text ‹
We need to specify the behavior of two FIFO buffers in a row.
Intuitively, that specification is just the conjunction of
two buffer specifications, where the first buffer has input
channel ‹inp› and output channel ‹mid› whereas
the second one receives from ‹mid› and outputs on ‹out›.
However, this conjunction allows a simultaneous enqueue action
of the first buffer and dequeue of the second one. It would not
implement the previous buffer specification, which excludes such
simultaneous enqueueing and dequeueing (it is written in
``interleaving style''). We could relax the specification of
the FIFO buffer above, which is esthetically pleasant, but
non-interleaving specifications are usually hard to get right
and to understand. We therefore impose an interleaving constraint
on the specification of the double buffer, which requires that
enqueueing and dequeueing do not happen simultaneously.
›
definition DBSpec
where "DBSpec ≡ TEMP ISpec inp q1 mid
∧ ISpec mid q2 out
∧ □[¬(Enq inp q1 mid ∧ Deq mid q2 out)]_vars"
text ‹
The proof rules of TLA are geared towards specifications of the
form ‹Init ∧ □[Next]_vars ∧ L›, and we prove that
‹DBSpec› corresponds to a specification in this form,
which we now define.
›
definition FullInit
where "FullInit ≡ TEMP (BInit inp q1 mid ∧ BInit mid q2 out)"
definition FullNxt
where "FullNxt ≡ TEMP (Enq inp q1 mid ∧ Unchanged (q2,out)
∨ Deq inp q1 mid ∧ Enq mid q2 out
∨ Deq mid q2 out ∧ Unchanged (inp,q1))"
definition FullSpec
where "FullSpec ≡ TEMP FullInit
∧ □[FullNxt]_vars
∧ WF(Deq inp q1 mid)_vars
∧ WF(Deq mid q2 out)_vars"
text ‹
The concatenation of the two queues will serve as the refinement mapping.
›
definition qc :: "'a list statefun"
where "qc ≡ LIFT (q2 @ q1)"
lemmas db_defs = buffer_defs DBSpec_def FullInit_def FullNxt_def FullSpec_def
qc_def vars_def
lemma DBSpec_stutinv: "STUTINV DBSpec"
unfolding db_defs by (simp add: bothstutinvs livestutinv)
lemma FullSpec_stutinv: "STUTINV FullSpec"
unfolding db_defs by (simp add: bothstutinvs livestutinv)
text ‹
We prove that ‹DBSpec› implies ‹FullSpec›. (The converse
implication also holds but is not needed for our implementation proof.)
›
text ‹
The following lemma is somewhat more bureaucratic than we'd like
it to be. It shows that the conjunction of the next-state relations,
together with the invariant for the first queue, implies the full
next-state relation of the combined queues.
›
lemma DBNxt_then_FullNxt:
"⊢ □BInv inp q1 mid
∧ □[Nxt inp q1 mid]_(inp,q1,mid)
∧ □[Nxt mid q2 out]_(mid,q2,out)
∧ □[¬(Enq inp q1 mid ∧ Deq mid q2 out)]_vars
⟶ □[FullNxt]_vars"
(is "⊢ □?inv ∧ ?nxts ⟶ □[FullNxt]_vars")
proof -
have "⊢ □[Nxt inp q1 mid]_(inp,q1,mid)
∧ □[Nxt mid q2 out]_(mid,q2,out)
⟶ □[ [Nxt inp q1 mid]_(inp,q1,mid)
∧ [Nxt mid q2 out]_(mid,q2,out)]_((inp,q1,mid),(mid,q2,out))"
(is "⊢ ?tmp ⟶ □[?b1b2]_?vs")
by (auto simp: M12[int_rewrite])
moreover
have "⊢ □[?b1b2]_?vs ⟶ □[?b1b2]_vars"
by (rule R1, auto simp: vars_def tla_defs)
ultimately
have 1: "⊢ □[Nxt inp q1 mid]_(inp,q1,mid)
∧ □[Nxt mid q2 out]_(mid,q2,out)
⟶ □[ [Nxt inp q1 mid]_(inp,q1,mid)
∧ [Nxt mid q2 out]_(mid,q2,out) ]_vars"
by force
have 2: "⊢ □[?b1b2]_vars ∧ □[¬(Enq inp q1 mid ∧ Deq mid q2 out)]_vars
⟶ □[?b1b2 ∧ ¬(Enq inp q1 mid ∧ Deq mid q2 out)]_vars"
(is "⊢ ?tmp2 ⟶ □[?mid]_vars")
by (simp add: M8[int_rewrite])
have "⊢ ?inv ⟶ #True" by auto
moreover
have "|~ ?inv ∧ ○?inv ∧ [?mid]_vars ⟶ [FullNxt]_vars"
proof -
have "|~ ?inv ∧ ?mid ⟶ [FullNxt]_vars"
proof -
have A: "|~ Nxt inp q1 mid
⟶ [Nxt mid q2 out]_(mid,q2,out)
⟶ ¬(Enq inp q1 mid ∧ Deq mid q2 out)
⟶ ?inv
⟶ FullNxt"
proof -
have enq: "|~ Enq inp q1 mid
∧ [Nxt mid q2 out]_(mid,q2,out)
∧ ¬(Deq mid q2 out)
⟶ Unchanged (q2,out)"
by (auto simp: db_defs tla_defs)
have deq1: "|~ Deq inp q1 mid ⟶ ?inv ⟶ mid$ ≠ $mid"
by (auto simp: Deq_def BInv_def)
have deq2: "|~ Deq mid q2 out ⟶ mid$ = $mid"
by (auto simp: Deq_def)
have deq: "|~ Deq inp q1 mid
∧ [Nxt mid q2 out]_(mid,q2,out)
∧ ?inv
⟶ Enq mid q2 out"
by (force simp: Nxt_def tla_defs
dest: deq1[unlift_rule] deq2[unlift_rule])
with enq show ?thesis by (force simp: Nxt_def FullNxt_def)
qed
have B: "|~ Nxt mid q2 out
⟶ Unchanged (inp,q1,mid)
⟶ FullNxt"
by (auto simp: db_defs tla_defs)
have C: "⊢ Unchanged (inp,q1,mid)
⟶ Unchanged (mid,q2,out)
⟶ Unchanged vars"
by (auto simp: vars_def tla_defs)
show ?thesis
by (force simp: actrans_def
dest: A[unlift_rule] B[unlift_rule] C[unlift_rule])
qed
thus ?thesis by (auto simp: tla_defs)
qed
ultimately
have "⊢ □?inv ∧ □[?mid]_vars ⟶ □#True ∧ □[FullNxt]_vars"
by (rule TLA2)
with 1 2 show ?thesis by force
qed
text ‹
It is now easy to show that ‹DBSpec› refines ‹FullSpec›.
›
theorem DBSpec_impl_FullSpec: "⊢ DBSpec ⟶ FullSpec"
proof -
have 1: "⊢ DBSpec ⟶ FullInit"
by (auto simp: DBSpec_def FullInit_def ISpec_def)
have 2: "⊢ DBSpec ⟶ □[FullNxt]_vars"
proof -
have "⊢ DBSpec ⟶ □(BInv inp q1 mid)"
by (auto simp: DBSpec_def intro: ISpec_BInv[unlift_rule])
moreover have "⊢ DBSpec ∧ □(BInv inp q1 mid) ⟶ □[FullNxt]_vars"
by (auto simp: DBSpec_def ISpec_def
intro: DBNxt_then_FullNxt[unlift_rule])
ultimately show ?thesis by force
qed
have 3: "⊢ DBSpec ⟶ WF(Deq inp q1 mid)_vars"
proof -
have 31: "⊢ Unchanged vars ⟶ Unchanged q1"
by (auto simp: vars_def tla_defs)
have 32: "⊢ Unchanged (inp,q1,mid) ⟶ Unchanged q1"
by (auto simp: tla_defs)
have deq: "|~ ⟨Deq inp q1 mid⟩_vars = ⟨Deq inp q1 mid⟩_(inp,q1,mid)"
by (simp add: Deq_visible[OF 31, int_rewrite]
Deq_visible[OF 32, int_rewrite])
show ?thesis
by (auto simp: DBSpec_def ISpec_def WeakF_def
deq[int_rewrite] deq[THEN AA26,int_rewrite])
qed
have 4: "⊢ DBSpec ⟶ WF(Deq mid q2 out)_vars"
proof -
have 41: "⊢ Unchanged vars ⟶ Unchanged q2"
by (auto simp: vars_def tla_defs)
have 42: "⊢ Unchanged (mid,q2,out) ⟶ Unchanged q2"
by (auto simp: tla_defs)
have deq: "|~ ⟨Deq mid q2 out⟩_vars = ⟨Deq mid q2 out⟩_(mid,q2,out)"
by (simp add: Deq_visible[OF 41, int_rewrite]
Deq_visible[OF 42, int_rewrite])
show ?thesis
by (auto simp: DBSpec_def ISpec_def WeakF_def
deq[int_rewrite] deq[THEN AA26,int_rewrite])
qed
show ?thesis
by (auto simp: FullSpec_def
elim: 1[unlift_rule] 2[unlift_rule] 3[unlift_rule]
4[unlift_rule])
qed
text ‹
We now prove that two FIFO buffers in a row (as specified by formula
‹FullSpec›) implement a FIFO buffer whose internal queue is the
concatenation of the two buffers. We start by proving step simulation.
›
lemma FullInit: "⊢ FullInit ⟶ BInit inp qc out"
by (auto simp: db_defs tla_defs)
lemma Full_step_simulation:
"|~ [FullNxt]_vars ⟶ [Nxt inp qc out]_(inp,qc,out)"
by (auto simp: db_defs tla_defs)
text ‹
The liveness condition requires that the combined buffer
eventually performs a ‹Deq› action on the output channel
if it contains some element. The idea is to use the
fairness hypothesis for the first buffer to prove that in that
case, eventually the queue of the second buffer will be
non-empty, and that it must therefore eventually dequeue
some element.
The first step is to establish the enabledness conditions
for the two ‹Deq› actions of the implementation.
›
lemma Deq1_enabled: "⊢ Enabled ⟨Deq inp q1 mid⟩_vars = ($q1 ≠ #[])"
proof -
have 1: "|~ ⟨Deq inp q1 mid⟩_vars = Deq inp q1 mid"
by (rule Deq_visible, auto simp: vars_def tla_defs)
have "⊢ Enabled (Deq inp q1 mid) = ($q1 ≠ #[])"
by (force simp: Deq_def tla_defs vars_def
intro: base_enabled[OF DB_base] elim!: enabledE)
thus ?thesis by (simp add: 1[int_rewrite])
qed
lemma Deq2_enabled: "⊢ Enabled ⟨Deq mid q2 out⟩_vars = ($q2 ≠ #[])"
proof -
have 1: "|~ ⟨Deq mid q2 out⟩_vars = Deq mid q2 out"
by (rule Deq_visible, auto simp: vars_def tla_defs)
have "⊢ Enabled (Deq mid q2 out) = ($q2 ≠ #[])"
by (force simp: Deq_def tla_defs vars_def
intro: base_enabled[OF DB_base] elim!: enabledE)
thus ?thesis by (simp add: 1[int_rewrite])
qed
text ‹
We now use rule ‹WF2› to prove that the combined buffer
(behaving according to specification ‹FullSpec›)
implements the fairness condition of the single buffer under
the refinement mapping.
›
lemma Full_fairness:
"⊢ □[FullNxt]_vars ∧ WF(Deq mid q2 out)_vars ∧ □WF(Deq inp q1 mid)_vars
⟶ WF(Deq inp qc out)_(inp,qc,out)"
proof (rule WF2)
show "|~ ⟨FullNxt ∧ Deq mid q2 out⟩_vars ⟶ ⟨Deq inp qc out⟩_(inp,qc,out)"
by (auto simp: db_defs tla_defs)
next
show "|~ ($q2 ≠ #[]) ∧ ○($q2 ≠ #[]) ∧ ⟨FullNxt ∧ Deq mid q2 out⟩_vars
⟶ Deq mid q2 out"
by (auto simp: tla_defs)
next
show "⊢ $q2 ≠ #[] ∧ Enabled ⟨Deq inp qc out⟩_(inp, qc, out)
⟶ Enabled ⟨Deq mid q2 out⟩_vars"
unfolding Deq2_enabled[int_rewrite] by auto
next
txt ‹
The difficult part of the proof is to show that the helpful
condition will eventually always be true provided that the
combined dequeue action is eventually always enabled and that
the helpful action is never executed. We prove that (1) the
helpful condition persists and (2) that it must eventually
become true.
›
have "⊢ □□[FullNxt ∧ ¬(Deq mid q2 out)]_vars
⟶ □($q2 ≠ #[] ⟶ □($q2 ≠ #[]))"
proof (rule STL4)
have "|~ $q2 ≠ #[] ∧ [FullNxt ∧ ¬(Deq mid q2 out)]_vars
⟶ ○($q2 ≠ #[])"
by (auto simp: db_defs tla_defs)
from this[THEN INV1]
show "⊢ □[FullNxt ∧ ¬ Deq mid q2 out]_vars
⟶ ($q2 ≠ #[] ⟶ □($q2 ≠ #[]))"
by auto
qed
hence 1: "⊢ □[FullNxt ∧ ¬(Deq mid q2 out)]_vars
⟶ ◇($q2 ≠ #[]) ⟶ ◇□($q2 ≠ #[])"
by (force intro: E31[unlift_rule])
have 2: "⊢ □[FullNxt ∧ ¬(Deq mid q2 out)]_vars
∧ WF(Deq inp q1 mid)_vars
⟶ (Enabled ⟨Deq inp qc out⟩_(inp, qc, out) ↝ $q2 ≠ #[])"
proof -
have qc: "⊢ ($qc ≠ #[]) = ($q1 ≠ #[] ∨ $q2 ≠ #[])"
by (auto simp: qc_def tla_defs)
have "⊢ □[FullNxt ∧ ¬(Deq mid q2 out)]_vars ∧ WF(Deq inp q1 mid)_vars
⟶ ($q1 ≠ #[] ↝ $q2 ≠ #[])"
proof (rule WF1)
show "|~ $q1 ≠ #[] ∧ [FullNxt ∧ ¬ Deq mid q2 out]_vars
⟶ ○($q1 ≠ #[]) ∨ ○($q2 ≠ #[])"
by (auto simp: db_defs tla_defs)
next
show "|~ $q1 ≠ #[]
∧ ⟨(FullNxt ∧ ¬ Deq mid q2 out) ∧ Deq inp q1 mid⟩_vars ⟶
○($q2 ≠ #[])"
by (auto simp: db_defs tla_defs)
next
show "⊢ $q1 ≠ #[] ⟶ Enabled ⟨Deq inp q1 mid⟩_vars"
by (simp add: Deq1_enabled[int_rewrite])
next
show "|~ $q1 ≠ #[] ∧ Unchanged vars ⟶ ○($q1 ≠ #[])"
by (auto simp: vars_def tla_defs)
qed
hence "⊢ □[FullNxt ∧ ¬(Deq mid q2 out)]_vars
∧ WF(Deq inp q1 mid)_vars
⟶ ($qc ≠ #[] ↝ $q2 ≠ #[])"
by (auto simp: qc[int_rewrite] LT17[int_rewrite] LT1[int_rewrite])
moreover
have "⊢ Enabled ⟨Deq inp qc out⟩_(inp, qc, out) ↝ $qc ≠ #[]"
by (rule Deq_enabledE[THEN LT3])
ultimately show ?thesis by (force elim: LT13[unlift_rule])
qed
with LT6
have "⊢ □[FullNxt ∧ ¬(Deq mid q2 out)]_vars
∧ WF(Deq inp q1 mid)_vars
∧ ◇Enabled ⟨Deq inp qc out⟩_(inp, qc, out)
⟶ ◇($q2 ≠ #[])"
by force
with 1 E16
show "⊢ □[FullNxt ∧ ¬(Deq mid q2 out)]_vars
∧ WF(Deq mid q2 out)_vars
∧ □WF(Deq inp q1 mid)_vars
∧ ◇□ Enabled ⟨Deq inp qc out⟩_(inp, qc, out)
⟶ ◇□($q2 ≠ #[])"
by force
qed
text ‹
Putting everything together, we obtain that ‹FullSpec› refines
the Buffer specification under the refinement mapping.
›
theorem FullSpec_impl_ISpec: "⊢ FullSpec ⟶ ISpec inp qc out"
unfolding FullSpec_def ISpec_def
using FullInit Full_step_simulation[THEN M11] Full_fairness
by force
theorem FullSpec_impl_Spec: "⊢ FullSpec ⟶ Spec inp out"
unfolding Spec_def using FullSpec_impl_ISpec
by (force intro: eexI[unlift_rule])
text ‹
By transitivity, two buffers in a row also implement a single buffer.
›
theorem DBSpec_impl_Spec: "⊢ DBSpec ⟶ Spec inp out"
by (rule lift_imp_trans[OF DBSpec_impl_FullSpec FullSpec_impl_Spec])
end
end